Mr. McMurry wants to get a gym membership. Planet fitness charges $25 a month. Everyday Fitn

Find x to the nearest tenth

jeka57 [31]

Answer:

x=30.6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

a couch ,a love seat,and a chair cost $1565.the couch costs twice as much as the chair,and the love seat costs $ 400 more than t

Art [367]

I'm guessing you are having a problem with translating the problem into an equation you can solve. To help this what you can first do is underline the important parts of this problem. twice as much, 400 more,
Lets look at this
First Let the chair=x
Next we know the couch cost twice as much as the chair
So now we know we should let the couch=2x
Lastly the love seat is 400 more than the couch. couch+400is the same thing as saying 2x+400
NOw 1565=chair(x)+couch(2x)+love seat(2x+400)
So that means 1565=x+2x+2x+400
Combine like terms and you now have 1565=5x+400
Now you isolate the variable by subtracting 400 from both sides which is 1165=5x Then you divide both sides by 5 and get 223=x

5 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

To visit her grandmother, Jessica takes a horse 3.31 kilometers and a motorcycle 1 kilometer. How many kilometers is Jessica’s j

umka21 [38]

The total distance she travelled 4.1 Km.

<h3>What is unitary method?</h3>

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Jessica takes a horse 3.31 kilometers

Through a motorcycle she travel 1 kilometer.

So, the total distance travelled

=3.31 + 1

=4.31 Km

Hence, the total distance they travelled is 4.31 Km.

Learn more about unitary method here:

brainly.com/question/22056199

#SPJ2

8 0

1 year ago

Read 2 more answers

The senior class is taking a trip to an amusement park. They received a special deal where for every three tickets they purchase

MariettaO [177]

A) No, the root 3 has multiplicity of 3.

B) No, there are two imaginary solutions.

C) No, the root −2 has multiplicity of 3.

D) Yes, the Fundamental Theorem of Algebra does not apply to this equation.

4 0

4 years ago