<em>For</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>image</em><em>,</em><em> </em><em>note</em><em> </em><em>that</em><em> </em><em>slope</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>thing</em><em> </em><em>as</em><em> </em><em>gradient</em><em>.</em>
1) y = 2x + 4
2) Substituting in x = 1 and y = 1,
1 = 4(1) + c
1 = 4 + c
c = -3
So, the equation is y = 4x - 3
The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
<h3>How to solve the trigonometric equations?</h3><u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>
The equation can be split as follows:
y = 1 - cos(x)
y = 2 - 2sin²(x)
Next, we plot the graph of the above equations (see graph 1)
Under the domain interval (-π, π), the curves of the equations intersect at:
(-π/3, 0.5) and (π/3, 0.5)
Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>
The equation can be split as follows:
y = 4cos⁴(x) - 5cos²(x) + 1
y = o
Next, we plot the graph of the above equations (see graph 2)
Under the domain interval [0, 2π), the curves of the equations intersect at:
(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
Read more about trigonometry equations at:
#SPJ1
