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aleksandrvk [35]
3 years ago
13

Help with the question above! Pleaseeeeee!

Mathematics
2 answers:
krek1111 [17]3 years ago
5 0
Honors Geometry B  Unit 6 <span>Lesson 7: Areas and Volumes of Similar Solids
</span>1.C
2.C
3.D
4.B
5.A
6.C
7.D
8.A
9.B
10. Workpad Answer: cost of operating AC at smaller warehouse = $ 125.00 per day. 

<span>larger warehouse is 2.5 times larger w r t length , width & height of smaller one. </span>

<span>volume of smaller warehouse = l*w*h cubic units </span>

<span>volume of larger one = 2.5*2.5*2.5 * l*w*h </span>

<span>= 15.625 l*b*h </span>

<span>so, larger ware house occupies 15.625 times space as smaller one. </span>

<span>its cost of operation will be 15.625 times more than the smaller one. </span>

<span>so cost / day = 15.625 * $ 125 </span>

<span>= $ 1953.125 </span>

= $ 1953.00 [rounded off to nearest dollar]

Hope this helps loves!!
SSSSS [86.1K]3 years ago
4 0
Question 5:
 the circumference is given by:
 C = 2 * pi * r
 Where,
 r: radio of the ball
 Substituting values we have:
 22 = 2 * pi * r
 Clearing r we have:
 r = 11 / pi
 The surface area is given by:
 A = 4 * pi * r ^ 2
 Substituting values we have:
 A = 4 * 3.14 * (11 / 3.14) ^ 2
 A = 154 in ^ 2
 Answer:
 
The surface area of the balloon is:
 
A = 154 in ^ 2

 Question 8:
 For this case we have that the scale factor is given by:
 V1 = (k ^ 3) * V2
 Substituting values we have:
 729 = (k ^ 3) * 2744
 Clearing k:
 k = (729/2744) ^ (1/3)
 k = 9/14
 Answer:
 the scale factor of a cube with volume 729 m ^ 3 to a cube with volume 2,744 m ^ 3 is:
 9:14

 Question 2:
 The volume of the cylinder is given by:
 V = pi * r ^ 2 * h
 Where,
 r : radio
 h: height
 Substituting values:
 V = pi * (2.8) ^ 2 * (13)
 V = 101.92 * pi
 Answer:
 
The volume of the cylinder is:
 
V = 101.92 * pi
 
option 3
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Complete the statement below to explain how this model shows that 3/4 ÷ 2/3 = 9/8.
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6 0
3 years ago
(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

t=1min Sugar=0.27 Kg

Step-by-step explanation:

Data

Tank = 2640 L (pure water)

Sol=0.09kg Sugar per liter

Vin = Vout = 3L/min

Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

\frac{3L}{min}*\frac{0.09Kg}{L}=0.27kg/min

7 0
3 years ago
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Which of the following points lie in the solution set to the following system of inequalities? y ≤ x − 5 y ≥ −x − 4
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Y ≤ x - 5
y ≥-x - 4

   x - 5 = -x - 4
+ x       + x
 2x - 5 = -4
     + 5  + 5
       2x = 1
        2     2
         x = ¹/₂
         y = x - 5
         y = ¹/₂ - 5
         y = -4¹/₂

The following points that lie in the solution set to the following system of inequalities is (¹/₂, -4¹/₂).
8 0
3 years ago
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Someone please help I’m begging!! I will mark brainlest!
lara31 [8.8K]

Answer:

.

Step-by-step explanation:

2(3x^2+23x+14)

2(3x^2+21x+2x+14)

2(3x(x+7)+2(x+7)

2(x+7)(3x+2)

7 0
3 years ago
A school district has a student population of $6,734 students. If the maximum class size is 25 students. How many more teacher m
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Answer:

53 teachers

Step-by-step explanation:

Basically, what we need to do here is to find how many teachers there need to be, first. If there are 6,734 students in the school district and if maximum class size is 25, then the number of teachers needed is:

6,734 / 25 = 269.36

Of course, it's obvious that we can't have a decimal number of teachers, so we need to find integer (269 or 270).

If we take 269 teachers and 25 students per class, we get:

269 • 25 = 6,725 students, which is not enough, since there are 6,734 students.

That means that the number of teachers needed is 270.

It is given that there are already 217 teachers, meaning that 270-217=53 teachers have to be supplemented.

8 0
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