(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate 3 L/min. The solution is mixed and drains from the tank at the same rate. (a) How much sugar is in the tank at the beginning
2 answers:
Answer:
t=0 Sugar = 0 Kg
t=1min Sugar=0.27 Kg
Step-by-step explanation:
Data
Tank = 2640 L (pure water)
Sol=0.09kg Sugar per liter
Vin = Vout = 3L/min
Sugar in the beginning = ?
if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water
, but if beginning is t= 1min then;
Answer: y(t)= 237.6(1-e^(-t/880))
Step-by-step explanation:
In the attachment
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