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Hatshy [7]
3 years ago
8

zack's science teacher gave each student in his class 15.0 grams of an unknown substance to identify. Each student was required

to verify the mass of their substance by taking four measurements. Which of Zack's measurements were the most accurate of the four recorded?
Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:60

Step-by-step explanation:

15.0 x 4 = 60

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HELP ME PLEASE!! look at screenshot!! (10 pts)
ivolga24 [154]

Answer:

C) 72 square yards

Step-by-step explanation:

I cut it into two shapes. One being the rectangle on top with values 12 yd and 3 yd. the other being the square 6yd by 6yd

12•3= 36

6•6= 36

36+36= 72

72 square yards

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5 0
3 years ago
Can you please show me how to do:
USPshnik [31]

Step-by-step explanation:

6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6

3 0
3 years ago
Read 2 more answers
4x5:):):):):):):)free
Kruka [31]

Answer:

The answer is 20

Step-by-step explanation:

Can i have brainiest

8 0
3 years ago
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Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win
Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Similarly,

P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

7 0
3 years ago
Here is my question.
s2008m [1.1K]

Answer:

5/8

Step-by-step explanation:

if 1/8 is used for one batch . for five batch=1/8*5=5/8

4 0
3 years ago
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