Answer:
2,000
Step-by-step explanation:
write out an equation that represents the problem. the original price X fell by 15% to a new price of 1700:
X - (X*15%) = 1700
X(1-0.15) =1700
X=1700/(1-0.15)
X=2,000
convert 15% to decimal form:
15%=0.15
A cross section is the two dimensional shape that is created when a slice is made through a solid figure by an intersection of a plane and the solid body.
A square pyramid is a pyramid with a square base.
Case 1: When the plane intersects the square pyramid at an angle perpendicular to the base but not through the vertex. In this case a trapezoid is formed.
Case 2: When the plane intersects the square pyramid at an angle perpendicular to the base and through the vertex. In this case a triangle is formed.
Case 3: When the plane intersects the square pyramid at an angle parallel to the base. In this case a square is formed.
<span>Therefore, a
cross section made by the intersection of a plane and a square
pyramid at an angle either parallel or perpendicular to the base can be of shapes:
-square
-triangle
-trapezoid</span>
Answer:
-12
Step-by-step explanation:
ds/dt = d/dt ( 1-12 t)
ds/dt = -12
When t=2
ds/dt = -12
<u>Value of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>3</u><u>0</u><u>°</u>
Answer:
Solution given:
x°+(5x)°=180°[being straight line which sum of angle is 180°]
adding like terms
(6x)°=180°
dividing both side by 6
(6x)°/6=180°/6
x=30°
Answer:
The current temperature on the X scale is 1150 °X.
Step-by-step explanation:
Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:



The difference between current temperature in Y linear scale with respect to freezing point is:


The change in X linear scale is:



Lastly, the current temperature on the X scale is:


The current temperature on the X scale is 1150 °X.