Expand.<br> Your answer should be a polynomial in standard form.<br> (7g+2)(5g+4)=

Flauer [41]

Answer:

6 m

Step-by-step explanation:

The volume of a cone is found by $\frac{\pi r^2h}{3}$ , so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.

4 0

3 years ago

A dolphin is 42 feet underwater and ascends at a constant rate for 14 seconds until it reaches the surface. Identify and interpr

Cloud [144]

Ok so, based on the graph lets say that x = seconds and y = depth of dolphin. the interception in both points is when they are at 0 i.e when x is equals 0 and y equals 0. So At 0 seconds, the dolphin is 42 feet below the surface. So we say that x = 0, y = -42 and then the y intercepts = -42 so the point of interception is(0 (seconds),-42(depth of the dolphin)) When the clock says it's 14 seconds, the dolphin is even with the surface (0 below the surface this time). So we say that x = 14, y = 0. In this case The x intercept = 14 (14,0). But we need to calculate The slope with the formula= (y2 - y1)/(x2 - x1) = 42/14 = 3. Therefore, the formula for this line is y = 3x - 42.

3 0

3 years ago

- a(-4-5a) - 3a(2 + a) =

Lorico [155]

Answer:

Let's simplify step-by-step.

(−a)(−4 − 5a) − 3a(2 + a)

Distribute:

= (−a)(−4) + (−a)(−5a) + −3a^2 + −6a

= 4a + 5a^2 + −3a^2 + −6a

Combine Like Terms:

= 4a+5a^2 + −3a^2+ −6a

= (5a2+ −3a^2) + (4a + −6a)

= 2a2 + −2a

Final Answer:

= 2a^2−2a!

4 0

3 years ago

Read 2 more answers

Simplify:<br> (7ty) (31)

rosijanka [135]

The answer to this question is option D, the last option!

6 0

2 years ago

Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the

uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21) - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21 nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21 over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>

9.9 trillion seconds
2,755,750,000 hours
114,822,917 days
314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0

3 years ago

Expand. Your answer should be a polynomial in standard form. (7g+2)(5g+4)=