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Aneli [31]
3 years ago
7

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot

ation reflection dilation translation must be used to make the two polygons coincide. A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a reflection across the x-axis and a 90° clockwise rotation about point D a translation 2 units down and a 90° counterclockwise rotation about point D a 90° counterclockwise rotation about point D and a reflection across the x-axis a reflection across the x-axis and a 90° counterclockwise rotation about point D

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0
I found the corresponding image. Pls. see attachment.

<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>

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3 years ago
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Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
I REALLY NEED HELP HURRY ITS DUE IN 5 MINS<br> BOTH QUESTIONS
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Answer:

(2. 16/24) (3. 0 (because there are no green shirts))

Step-by-step explanation:

Hope it helps!

3 0
3 years ago
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vova2212 [387]
Let's call animals "a", and birds "b", birds of prey, "p"

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and p=\frac{4}{15} b
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we substitude b into the last one:

and p=\frac{4}{15}* \frac{3}{28} a
so:
p=\frac{4*3}{15*28} a

p=\frac{4*1}{5*28} a


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3 years ago
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Steps to solve:

7 = 11t

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The fraction can't be simplified any further.

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