All categories

3 years ago

I have this problem for hw and it’s due tomorrow. can someone please help me? (it’s y-4 not 4-4)

Mathematics

1 answer:

Vesnalui [34]3 years ago

3 0

Answer:

All real numbers

Step-by-step explanation:

$-2(y - 4) = 20 - 2y - 12$

Start by distributing -2 inside the parentheses.

$-2y + 8 = 20 - 2y - 12$

Combine like terms on the right side of the equation.

$-2y + 8 = 8 - 2y$

Subtract 8 from both sides of the equation.

$-2y =- 2y$

Divide both sides by -2 to isolate y.

$0=0$

This is a true statement, so there are infinite solutions.

You might be interested in

20 POINTS! Which of the following equations shows how substitution can be used to solve the following system of equations?

natima [27]

Answer:

Is there a photo or no

Step-by-step explanation:

5 0

3 years ago

3\10 x 2\3 A.5\30 B.6\13 C.1\5 D.5\13

kow [346]

3/10 times 2/3 3 times 2 is 5 and 10 times 3 is 30 5/30 a

3 0

2 years ago

Read 2 more answers

Uhuhuhuu EEEEEEEEEEEEEEEEEEEE help?

lianna [129]

Answer:

4 parts 3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The figure shows the graphs of three functions. One is the position function of a car, one is the velocity of the car, one is it

Anika [276]

a) Is the twitch - initial positive twitch or sudden movement, which is what makes the car jolt into action.

b) is the acceleration - graph shows the acceleration and deceleration of the car.

c) is the velocity - starts at 0 and increases until the car travels at its right speed.

d) is the position - assuming that the car is going on only one direction. This graph is the only one that does not go back to the x-axis.

5 0

3 years ago

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

8 0

2 years ago

Read 2 more answers