Answer:
4m
Step-by-step explanation:
We are looking for the circumference
We need to find the radius
r = d/2 = 1.2/2 = .6
C = 2*pi*r
C = 2*pi*(.6)
C = 1.2*pi
We can approximate pi by 3.14
C =1.2*3.14
C =3.768 m
To the nearest meter
C = 4m
Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, ![\frac{AE}{ED}=\frac{AB}{CD}](https://tex.z-dn.net/?f=%5Cfrac%7BAE%7D%7BED%7D%3D%5Cfrac%7BAB%7D%7BCD%7D)
⇒ ![\frac{2x+10}{x+3}=\frac{10}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B10%7D%7Bx%2B3%7D%3D%5Cfrac%7B10%7D%7B4%7D)
⇒ ![8x+40=10x+30](https://tex.z-dn.net/?f=8x%2B40%3D10x%2B30)
⇒ ![x=5](https://tex.z-dn.net/?f=x%3D5)
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer:
95.2
Step-by-step explanation:
15!!! is the answer to your question:)