A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
Answer:
Step-by-step explanation:
![As\ range=51,\\x-4=51\\x=51+4\ [Adding\ 4\ on\ both\ the\ sides]\\x=55 \\2. x\ is\ the\ lowest\ observation\ or\ x](https://tex.z-dn.net/?f=As%5C%20range%3D51%2C%5C%5Cx-4%3D51%5C%5Cx%3D51%2B4%5C%20%5BAdding%5C%204%5C%20on%5C%20both%5C%20the%5C%20sides%5D%5C%5Cx%3D55%20%5C%5C2.%20x%5C%20is%5C%20the%5C%20lowest%5C%20observation%5C%20or%5C%20x%3C4.%5C%5CHence%2C%5C%5CHighest%5C%20observation%3D48%5C%5CLowest%5C%20observation%3Dx%5C%5CHence%2C%5C%5CAs%5C%20the%5C%20range%5C%20is%5C%2051%2C%5C%5C48-x%3D51%5C%5C-x%3D51-48%20%5BSubtracting%5C%2048%5C%20from%5C%20both%5C%20the%5C%20sides%5D%5C%5C-x%3D3%5C%5Cx%3D-3)
Answer: 15m + 5n
Step-by-step explanation:
so, first off, we take the number outside of the parentheses and multiply it by everything that's inside of the parentheses.
(5)3m + 5(n)
then, we just multiply all of those together.
15m + 5n
The reason why Fiona cannot make a valid prediction based on the mean of the population is that the variation of Fiona’s samples is too large.
<h3>Why can't Fiona use the means she recorded?</h3><h3 />
Mean is quite sensitive to outliers so it is best used when the variation between variables is not too much.
In Fiona's case, there variation is quite high with high variable of 95 compared to a low value of 45.
Find out more on effect of outliers at brainly.com/question/16815987.
#SPJ1
Cost = fix cost + hourly cost - discount
Cost = 4* [5 + 4x - 4x(20/100)] = 4*[5 + 4x - 0.8x] = 4*[5 + 3.2x] = 20 + 12.8x
Answer: option B) 12.8x + 20
