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Ostrovityanka [42]
2 years ago
7

Gabrielle and Rob earn a total of $2,560 this week. With their total earnings from the week, Gabrielle buys 2 train tickets that

cost $215.80 each, and Rob buys 2 suitcases that cost $36.50 each. Which statement is true?
A) Gabrielle and Rob have $ 2,055.40 of the $2 ,560 left because 2,560 − 2( 215.80 ) − 2(36.50 ) is equal to 2,055.4.

B)Gabrielle and Rob have $2,091.90 of the $2,560 left because 2,560−2(215.80)−36.50 is equal to 2,091.9.

C)Gabrielle and Rob have $2,271.20 of the $2,560 left because 2,560−215.80−2(36.50) is equal to 2,271.2.

D)Gabrielle and Rob have $2,307.70 of the $2,560 left because 2,560−215.80−36.50 is equal to 2,307.7.
Mathematics
1 answer:
wariber [46]2 years ago
4 0

Answer:

A

Step-by-step explanation:

215.80 + 215.80 = 431.60

36.50 + 36.50  = 73

431.60 + 73 = 504.60

2560 - 504.60 = 2055.40

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

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<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

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Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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Evaluate................
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Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

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2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

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Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

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In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

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