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3 years ago

The perimeter of a rectangle is twice the sum of its length and width the peremeter is 28 meters

Mathematics

1 answer:

Roman55 [17]3 years ago

3 0

The right answer is 12 m

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Ms Ramos’s thumb measures 4 centimeters. Express the length in meters.

viva [34]

Answer:

1.1%

Step-by-step explanation:

it goes to meters and this is the answer

8 0

3 years ago

PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!

shutvik [7]

Answer:

$m\angle N = 32\degree$

$m\widehat {NQ}=106\degree$

Step-by-step explanation:

By inscribed angle theorem:

$m\angle N = \frac{1}{2} \times m\widehat {MP}$

$m\angle N = \frac{1}{2} \times 64\degree$

$m\angle N = 32\degree$

Again by inscribed angle theorem:

$m\angle P= \frac{1}{2} \times m\widehat {NQ}$

$53\degree = \frac{1}{2} \times m\widehat {NQ}$

$2\times 53\degree = m\widehat {NQ}$

$m\widehat {NQ}=106\degree$

5 0

3 years ago

Plssss help quick i need it for sum important

Vanyuwa [196]

(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

Step-by-step explanation:

(a)

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

7 0

3 years ago

Name the property 3. 7/9* 1= 7/9

Nutka1998 [239]

Answer:

identify-multiplication

Step-by-step explanation:

anything you multiply by 1 is most likely going to be in the identify property

6 0

3 years ago

The next two terms are and

kherson [118]

Answer:

The next two terms are 92 and 105.

Step-by-step explanation:

79 + 13 = 92

92 + 13 = 105

4 0

2 years ago