Answer:
9/16
Step-by-step explanation:
Answer:
no possible answers
Step-by-step explanation:
V
W
X
w = 35
x = 78
48°
?°
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin X}{78}=\frac{\sin 48}{35}
78
sinX
=
35
sin48
Plug in values.
\sin X=\frac{78\sin 48}{35}\approx 1.6561513
sinX=
35
78sin48
≈1.6561513
Evaluate.
X=\sin^{-1}(1.6561513)= \text{ERROR}
X=sin
−1
(1.6561513)=ERROR
Sine cannot be greater than 1.
\text{No Possible Triangles}
No Possible Triangles
\{\}
{}
Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>


<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
Answer:
X is equal
Step-by-step explanation:
look at the angle