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andrew-mc [135]
3 years ago
8

I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the

2 terms on the left side). Here goes: x÷2 - (10x-25)÷10 = 3(x+3) - (x-14). Please help
Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0

x/2 - (10x - 25)/10 = 3(x + 3) - (x - 14)


Multiply each term by 10 to eliminate the fractions:-


5x - (10x - 25) = 30(x + 3) - 10(x - 14)


5x - 10x + 25 = 30x + 90 - 10x + 140

5x - 10x - 30x + 10x = 90 + 140 - 25

-25x = 205

x = -8.2 answer

Ugo [173]3 years ago
7 0

Assuming the equation is:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)


When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.


Here the denominators are 2 and 10, hence the LCM is 10.


Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

5x-(10x-25)=30(x+3)-10(x-14)

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5


In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)

x-(2x-5)=6(x+3)-2(x-14)

Now, distribute, i.e. remove parentheses and distribute:

x-2x+5=6x+18-2x+28

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

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