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Stolb23 [73]
3 years ago
9

hallie has 10 times as many pages to read for her homework assignment as Janet altogether they have to read 264 pages how many p

ages does each girl have to read
Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0
Janet must read 24 pages to Hallie's 240 pages
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What is the perimeter of this polygon? Round your answer to the nearest<br> tenth
bulgar [2K]

Answer:

A

Step-by-step explanation:

pythagorean theorem

A^2+B^2=C^2 do that for all sides then add

6 0
3 years ago
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What is the area of rectangle RSTU? Show step by step!
pickupchik [31]

Step-by-step explanation:

We only know 1 side, and that is the width of 4. We only have the diagonals at our side. Half of the diagonal is 5. As a result, the diagonal is 10. I want you to imagine a triangle that has a base of 4 and a hypotenuse of 10. Use the Pythagorean Theorem to find b, or the height.

a² + b² = c²

4² + b² = 10²

16 + b² = 100

100 - 16 = 84

b² = 84

b = √84

b ≈ 9.165

Now we know the length of the rectangle, which is about 9.165. Multiply that by 4 to get the area.

9.165 * 4

36 + 0.4 + 0.24 + 0.020

36.4 + 0.24 + 0.02

36.64 + 0.02

36.66 u²

The area of rectangle RSTU is about 36.66 units squared.

8 0
2 years ago
Can you answer number six please
BaLLatris [955]
So,

1. Tawni swam a 50-m Freestyle in 40.8 secs.
2. Pepita swam a 100-m Butterfly in 60.2 secs.
3. Susana swam a 200-m Medley in 112.4 secs.

Manipulate the distances so that they are the same.

Tawni would swim a 200-m in 163.2 secs.
Pepita would swim a 200-m in 120.4 secs.
Susana woulld swim a 200-m in 112.4 secs.

Susana swam the fastest.

8 0
3 years ago
an airplane travels 4688 kilometers against the wind in 8 hours and 5808 kilometers with the wind in the same amount of time. wh
Vladimir [108]

The speed of wind is 656 kmph and speed of plane is 70 kmph.

<u>SOLUTION: </u>

Given that, an air-plane travels 4688 kilometers against the wind in 8 hours

And 5808 kilometers with the wind in the same amount of time.  

We have to find the rate of the plane in still air and the rate of wind

Now, let the speed of wind be a kmph and speed of plane be b kmph.

And we know that, \text { distance }=\text { speed } \times \text { time }

\begin{array}{l}{\text { Then, while travelling with wind } \rightarrow 5808=(a+b) \times 8 \rightarrow a+b=726 \rightarrow a=726-b \rightarrow(1)} \\\\ {\text { While travelling against wind } \rightarrow 4688=(a-b) \times 8 \rightarrow a-b=586 \rightarrow(2)}\end{array}

Substituting (1) in (2) we get,

\Rightarrow 726-b-b = 586\Rightarrow -2b=586-726 \Rightarrow -2b=-140

\Rightarrow b=\frac{140}{2} \Rightarrowb=70\Rightarrow (3)

On substituting (3) in (1) we get,

a=726-70=656\Rightarrow a=656

Hence, the speed of wind is 656 kmph and speed of plane is 70 kmph.

4 0
3 years ago
What instrument is used to measure milliliters
almond37 [142]
Measuring cups
 that should be correct

3 0
3 years ago
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