Answer:
5cm by 1.95cm
Step-by-step explanation:
Let the length of the rectangle be x
Let the width be y
Perimeter of a rectangle = 2x + 2y
If the initial perimeter of a rectangle is about 13.9 cm, then;
13.9 = 2x + 2y ..... 1
If when the width is double the perimeter is 17.8cm, then;
17.8 = 2x + 4y ..... 2
Subtract 1 from 2;
13.9 - 17.8 = 2y - 4y
- 3.9 = -2y
y = 3.9/2
y = 1.95 cm
Substitute y = 1.95 into 1 to get x;
From 1;
13.9 = 2x + 2y
13.9 = 2x + 2(1.95)
13.9 = 2x + 3.9
2x = 13.9-3.9
2x = 10
x = 5 cm
Hence the dimension of the smaller triangle is 5cm by 1.95cm
Answer:
-40
Step-by-step explanation:
-4 * 2 = -8
-8*-1= 8
12+8 = 20
20*(-2) =-40
Answer:
no solution
Step-by-step explanation:
6-2.25=0.5
no solution
Answer:
3y²z³ / 2x
Step-by-step explanation:
we can take one term at a time:
9/6 can be simplified to 3/2
x²÷x³ = x^-1 which equals 
y³÷y = y²
z⁵÷z² = z³
put it all together:
3··y²·z³ / 2 or
3y²z³ / 2x
If sine (theta) = 4/7 then theta is found by:
arc sine (4/7) = theta
theta = 34.85 Degrees
cosine (34.85) = 0.82065
