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saul85 [17]
3 years ago
9

Can someone help with this question

Mathematics
2 answers:
eduard3 years ago
7 0
Now, as you can see - these are ordered pairs. So, in order to find possible solutions - we have to plot this inequality on a graph! 

So, let's do this. I am using GeoGebra in order to graph this inequality. 

Alright, so... Now I'm going to go through, and look at each ordered pair and see if they are covered by the shaded region!

Answer A: False
Answer B: False
Answer C: True
Answer D: True
Answer E: True
Answer F: True

Hopefully, this helps you! =)
Serga [27]3 years ago
3 0
C d e f are correct but a and b aren't
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If the length of room is four times the height and breadth is twice of its height and the volume of the room is 512 m^2 find its
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Let  \: x  \: (x>0)  \: be \:  the \:  height \Rightarrow the \: width, length: 2x,4x \\ Volume:V=hwl = 512 \\ \Leftrightarrow x2x4x = 512 \\ \Leftrightarrow 8{x }^{3}  = 512 \\\Leftrightarrow  {x}^{3}  = 64 \\ \Leftrightarrow x = 4 \\ \Rightarrow The \:  height \: is \: 4 \: m, the \: width \: is \: 8 \: m

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3 years ago
In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the
hjlf

Answer:

2 m/ s

a = F / m

a= 7.92 / 3.6

ie . 2.2 m/ s

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3 years ago
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What is the sum of 3 sixteen and 2 nines
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16+16+16+9+9=32+16+9+9=48+9+9=57+9=66

The answer is 66

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3 years ago
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A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 4 feet per second.
Ad libitum [116K]

Let d_m,\ d_e represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of v_e = 4 feet per second, and the miners one descends with a velocity of v_m = 15 feet per second.

If we start counting time (t=0) when the equipment elevator begins to descend, after t seconds its depth will be

d_e(t) = v_et = 4t

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

d_m(t) = v_m(t-30) = 15(t - 30)

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when t = 44. Let's plug this value into the two equations:

d_e(44) = 4\cdot 44 = 176

d_m(44) = 15(44-30) = 15\cdot 14 = 210

So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.

7 0
3 years ago
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
2 years ago
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