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2 years ago

What two numbers have a sum of 9 and a product of -10

Mathematics

1 answer:

mylen [45]2 years ago

8 0

Answer:

-2

Step-by-step explanation:

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Complete the equation of the line through (-10,-7) and (-5, -9).<br>Use exact numbers,

steposvetlana [31]

Answer:

$y=\frac{-5}{2}*x + 18$

Step-by-step explanation:

A line in 2-dimensional space has the following general equation:

$y=m*x+b$

Where m is the slope of the line, and b just a number

the slope can be obtaine using th following formula:

$m=\frac{x_{2} - x_{1} }{y_{2} - y_{1}}$

The point 2 is the one with the smallest value for x, that is (-10,-7) and the Point 1 is any other that belongs to the line, in this case, (-5,-9)

$m=\frac{-5 - (-10) }{-9 - (-7)}$

Resulting that $\frac{-5}{2}$

To find the other term we can use any other point, I prefer us the first one so...

We have the following equation:

$-7=\frac{-5}{2}*(-10)+b$

Resulting that b=18

I just have to eval the point (-10,-7) in the equation stated at the beginning knowin that m was calculated previously.

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2 years ago

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What is the 3 digit number of the ones period in 288,322,170

AnnZ [28]

Answer:

170

The ones period consists of the ones, tens, and hundreds digits.

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3 years ago

What is the range of range of the relation shown in the table?

seropon [69]

-2Step-by-step explanation:

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2 years ago

What is the solution to x 4 + 4x 3 ≤ 12x 2?

andriy [413]

Answer:

-6,2

Step-by-step explanation:

im not sure what the answer is

4 0

2 years ago

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The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

7 0

3 years ago