Using the least common multiple of 4 and 10, it is found that the smallest number of candies each order could have contained is 20 candies.
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- There are boxes of 4 candies and of 10 candies.
- Thus, the smallest possible number of equal candies on two orders in the<u> least common multiple of 4 and 10.</u>
- To find this multiple, we factor both numbers by their prime factors, thus:
4 - 10|2
2 - 5|2
1 - 5|5
1
Thus, lcm(4,10) = 2*2*5 = 20.
- The smallest possible number is 20 candies, one order with 20/4 = 5 boxes of 4 candies, and the other with 20/10 = 2 boxes of 10 candies.
A similar problem is given at brainly.com/question/24540608
Answer:
Because he's an idiot
Step-by-step explanation:
The answer would be B) x = 4.
1.5x + 6 - 3 = 4.5x - 9
1.5x + 3 = 4.5x - 9
3 = 4.5x - 9 - 1.5x
3 = 3x - 9
3 + 9 = 3x
12 = 3x
12/3 = x
4 = x
x = 4.
Answer: half life = 1.98 seconds
Step-by-step explanation:
Given that the amount of sodium-24 in the patient’s body in milligrams after t hours is given by
S(t) = 5e–0.35t.
From the equation above, decay constant K = 0.35
Half life = ln2/K
Half life = ln2/ 0.35
Half life = 1.98 seconds
He is fully recovered, Hehe
