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3 years ago

Find a + b, if b^a = 64 and a^b = 81

1 answer:

3 0

$\bf \begin{array}{llll}
b^a=64\qquad \boxed{64=4^3}\qquad b^a=4^3
\\\\\\
a^b=81\qquad \boxed{81=3^4}\qquad a^b=3^4
\end{array} \qquad 
\begin{cases}
a=3\\
b=4
\end{cases}
\\\\\\
a+b\implies 3+4$

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2 years ago

find the z scores that seperate the middle 82% of the distribution from the area in the tails of the standard normal distributio

Anna [14]

Answer:

Step-by-step explanation:

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3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

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Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

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Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

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Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

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Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

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Confidence Interval is ($106.40, $136.40)

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3 years ago

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2 years ago

Read 2 more answers

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(0, -32)

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3 years ago