Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
45 pages total
3 on last page
45-3=42
there are 42 on the rest of the pages
on each page, there are 2 more pages in album than then stamps on pages
amount of stamps on pages with equal number of stamps is
A=numberofpgest times number of stamps on pages
number of pages=p
number of stamps per papge=s
a=ps
2 more pages than stamps on pages
p=2+s
total number of stamps per page is s=(45-3)/(p-1)
(what I did is I first got rid of number of stamps on last page, then got rid of the last page)
P=2+s
s=(45-3)/(2+s-1)
s=42/(s+1)
times s+1 both sides
s^2+s=42
minus 42
s^2+s-42=0
factor
(s-6)(s+7)=0
set equal to zero
s-6=0
s=6
s+7=0
s=-7, false, no negative stamps
6 stamps per page
sub
p=2+s
p=2+6
p=8
8 pages
check
last page is 3 so 8-1=7 page left
7*6=42
3+42=45
correct
there are
8 pages in the album
6 stamps per page
Answer:
15 + x
Step-by-step explanation:
Answer:
square,rectangle,rhombus,paralellagram
Step-by-step explanation:
Answer:
<h2>y = 2x - 5</h2>
Step-by-step explanation:
2x - y = 5 <em>subtract 2x from both sides</em>
2x - 2x - y = -2x + 5
-y = -2x + 5 <em>change the signs</em>
y = 2x - 5
