Answer:
-3 was the low and the high temp. is 7
Step-by-step explanation:
Answer:
(1): "*-5x2y" was replaced by "*(-5x2y)".
(2): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(3x • (y2)) • (0 - (5x2 • y))
STEP
2
:
Equation at the end of step
2
:
3xy2 • -5x2y
STEP
3
:
Multiplying exponential expressions :
3.1 x1 multiplied by x2 = x(1 + 2) = x3
Multiplying exponential expressions :
3.2 y2 multiplied by y1 = y(2 + 1) = y3
I believe the answer is ( -3•5x3y3)
If you need anything else just tell me but I need more info for the
Answer
Answer:
|CE|=2
Step-by-step explanation:
The quadrilateral is shown in the attachment
Recall that the diagonals of a rectangle are congruent.
This implies that:
|AC|=|BD|
We substitute the expressions to get:
![2x-6=5x-21](https://tex.z-dn.net/?f=2x-6%3D5x-21)
This is now a linear equation in one variable.
Group similar terms to get:
![-6+21=5x-2x](https://tex.z-dn.net/?f=-6%2B21%3D5x-2x)
Simplify to get:
15=3x
Divide both sides by 3 to get:
![5=x](https://tex.z-dn.net/?f=5%3Dx)
Recall again that the diagonals of a quadrilateral bisect each other.
![|CE|=\frac{1}{2}|AC|](https://tex.z-dn.net/?f=%7CCE%7C%3D%5Cfrac%7B1%7D%7B2%7D%7CAC%7C)
![|CE|=\frac{1}{2}|2x-6|](https://tex.z-dn.net/?f=%7CCE%7C%3D%5Cfrac%7B1%7D%7B2%7D%7C2x-6%7C)
Plug x=5
![|CE|=\frac{1}{2}|2*5-6| =10-6=\frac{1}{2}*4=2](https://tex.z-dn.net/?f=%7CCE%7C%3D%5Cfrac%7B1%7D%7B2%7D%7C2%2A5-6%7C%20%3D10-6%3D%5Cfrac%7B1%7D%7B2%7D%2A4%3D2)