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Answer:
(x - 3)² - 16 = 0
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Subtract 7 from both sides
x² - 6x + 7 = 0 ← in standard form
with a = 1, b = - 6
Given a quadratic in standard form then the x- coordinate of the vertex is
= -
= -
= 3
Substitute x = 3 into the equation for y
y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)
y = (x - 3)² - 16 = 0
Answer:
- 5yz^2 - 3z^2 - 5y + 7
Step-by-step explanation:
The polynomial is:
( 1 )
this polynomial is the result of the sum of two polynomials, one of them given by
( 2 )
if you find to know what is the other polynomial, you can take the difference between the polynomial (1) and (2). It is necessary to take the difference between simmilar terms, as follow:
- yz^2 - 3z^2 - 4y + 4
<u>- (4yz^2 + y - 3 )</u>
<u />
- yz^2 - 3z^2 - 4y + 4
<u> - 4yz^2 - y + 3 </u>
- 5yz^2 - 3z^2 - 5y + 7
hence the other polynomial is - 5yz^2 - 3z^2 - 5y + 7