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FromTheMoon [43]
3 years ago
10

The figure shows an aerial view of a playground. If David runs around the field three times, he covers a distance of ___yards.

Mathematics
1 answer:
galben [10]3 years ago
5 0
The first thing we must do for this case is to find the perimeter of the figure.
 We have then that the perimeter is:
 P = ((35) * (280/180) * pi) + 45
 P = 216.04 yards.
 Then,
 As David runs the field three times then:
 d = 3 * P
 d = 3 * 216.04
 d = 648.12 yards.
 Answer:
 
he covers a distance of 648.12 yards
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550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,
EastWind [94]

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Answer:

  • adult: 325
  • children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

  1.50a +1.00(550 -a) = 712.50

  0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

  a = 325

  c = 550 -325 = 225

325 adult and 225 children's tickets were sold.

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Step-by-step explanation:

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The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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