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3 years ago

Determine the maximum number of zeros and the x-intercepts of the function: (x^2-x-2)(3x-2)

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

Step-by-step explanation:

note that zeros and x-intercepts are the same with different names

There are 2 zeros from the quadratic factor and 1 from the linear factor.

To find them equate the function to zero, that is

(x² - x - 2)(3x - 2) = 0

(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x + 1 = 0 ⇒ x = - 1

3x - 2 = 0 ⇒ x = $\frac{2}{3}$

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The equation y= 1/2 x +4 is graphed below.which equation would intersect this line at (4, 6)?

Anton [14]

Answer:

we have the equation y = (1/2)*x + 4.

now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:

f(4) = 6.

if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).

If we want to construct f(x), an easy example can be:

f(x) = y = k*x.

such that:

6 = k*4

k = 6/4 = 3/2.

then the function

f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)

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3 years ago

Determine the largest integer value of x in the solution of the following inequality.

Aleonysh [2.5K]

Answer:

x = 0

Step-by-step explanation:

Add 2x - 8 to the inequality.

... 1 ≥ 2x

Divide by 2.

... 1/2 ≥ x

The largest integer satisfying this requirement is x = 0.

6 0

4 years ago

Given the numbers 9 and 6 as legs of a right triangle, what is the length of the hypotenuse? Round your answer to the nearest

Ivahew [28]

$hypotensuse \: = \sqrt{ {6}^{2} + {9}^{2} } = \sqrt{36 +81 } = \sqrt{117} = 10.82$

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3 years ago

If m 6=51, then m 7=

Sophie [7]

Answer:

m 7=129

Step-by-step explanation:

if 6 and 7 are right next to each other. it makes 180 degrees so you would take 180-51 to get your answer

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3 years ago

Please solve 5x =9(x-4) i need it fast

Sveta_85 [38]

Answer:

i think the answer is "x = 9"

Step-by-step explanation:

sry if im wrong

have a good day :)

-XxMissNobodyxX

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2 years ago