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pashok25 [27]
3 years ago
13

(x + 4)(2x - 1)(x-3)=0

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

2x^{3} + x^{2} - 25x + 12

Step-by-step explanation:

There are three different enclosed brackets.

First multiply two of the brackets, then multiply the third by the answer

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Solve (x - 3)^2 = 5 p<br><br> please help
wel

Hello!

Let's solve !

⇒ (x - 3)² = 5

⇒ x² - 6x + 9 = 5

⇒ x² - 6x + 4 = 0

⇒ x = -(-6) ± √36 - 4(1)(4) / 2

⇒ x = 6 ± √20 / 2 = 6 ± 2√5 / 2

⇒ x = 3 ± √5

∴ The solutions are x = 3 + √5 and x = 3 - √5.

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2 years ago
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Answer:

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A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

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2 years ago
Write the explicit formula for the following sequence. 4, 20, 100, 500, ...
EastWind [94]
The answer would be 5x
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