All categories

3 years ago

Question 5 (1 point)

Mathematics

1 answer:

ElenaW [278]3 years ago

3 0

Answer:

The volume of the shape is 560 ft^3

Step-by-step explanation:

To find the volume of the figure, we need to multiply the base area by the height of the figure

mathematically, we have the base area as a rectangular shape and its area is the product of its side lengths

We have this as 8 ft * 10 ft = 80 ft^2

So multiplying this by the height which is 7 ft, we have this as;

7 ft * 80 ft^2 = 560 ft^3

You might be interested in

Given that f (x) = x^2 - 5x and g (x) x + 4

velikii [3]

1) (x-2)^2
2)-4x(x+5)

pls mark as brainliest:))

8 0

3 years ago

Solve using the quadratic formula. h2 + 8h + 8 = 0 Write your answers as integers, proper or improper fractions in simplest form

Marina86 [1]

A=1 b=8 c=8
h = [-8 +-sq root(64 - 4*1*8)] / 2
h = [-8 +-sq root(32)] / 2
h1 = -4 + 2.8284271247 
h1 = -1.1715728753 
h2 = -4 - 2.8284271247
h2 = - 6.8284271247

3 0

3 years ago

If triangle ABC is similar to triangle PQR, find the value of x and y.

tester [92]

Answer:

x = 9

y = 6

Step-by-step explanation:

ΔABC ~ ΔPQR

Therefore, corresponding sides of these similar triangles will be in the proportional.

$\frac{AB}{PQ}=\frac{BC}{QR}= \frac{AC}{PR}$

$\frac{6}{x}= \frac{4}{y}= \frac{8}{12}$

$\frac{6}{x}= \frac{8}{12}$

x = $\frac{12\times 6}{8}$

x = 9

Similarly, $\frac{4}{y}= \frac{8}{12}$

y = $\frac{12\times 4}{8}$

y = 6

6 0

3 years ago

Help with these two math questions thank u :)

Tju [1.3M]

Answer:

1.) - (4, 4) 2.) - (3,5) Hope this helps!!

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago