The expected enrolment in 7 years is 1845.
<h3>What is the expected enrolment?
</h3>
The formula for calculating future value of the number of students is an exponential equation with this form:
FV = P (1 + r) ^n
- FV = Future population
- P = Present population
- R = rate of growth of the population
- N = number of years
1500 x (1.03)^7 = 1845
To learn more about future value, please check: brainly.com/question/18760477
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Answer:
B
Step-by-step explanation:
is the only one with a constant rate of change which would be -2
Answer:
a) 
b) 
c) term number 17 is the one that gives a value of 40
Step-by-step explanation:
a)
The sequence seems to be arithmetic, and with common difference d = 3.
Notice that when you add 3 units to the first term (-80, you get :
-8 + 3 = -5
and then -5 + 3 = -2 which is the third term.
Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:
That in our case would give:
b)
Therefore, the term number 20 can be calculated from it:
c) in order to find which term renders 20, we use the general form we found in step a):
so term number 17 is the one that renders a value of 40
I’m think it is the median
Answer:
Step-by-step explanation:
This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).
350000 passengers
(350000 passengers) * 1
(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)
[note: passengers and carriages cancel. Leaving only trains]
(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]
729.1667 trains [oh, but don’t just round this number either up or down]
729 full trains can carry 729*32*15 = 349920 passengers
730 full trains can carry 730*32*15 = 350400 passengers
Now, we can say that 730 trains are adequate to carry 350000 passengers.
