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kotykmax [81]
3 years ago
11

The magnitude of a vector can be positive or negative The magnitude of a vector can be less than the magnitude of one of its com

ponents. If the magnitude of vector A is less than the magnitude of vector B, then the x-component of A is less than the x-component of B. None of the statements are accurate
Physics
1 answer:
NARA [144]3 years ago
8 0

Answer:

If magnitude of vector A is less than magnitude of vector B then its x-component will be also less      

Explanation:

In first case magnitude can never be negative -ve sign shows the direction only so it is incorrect statement.

The magnitude of any vector can never be less than its component because component of vector is found with the multiplication of sine and cos angle which values lies between 0 and 1 so after multiplication it gives less value than the vector

If magnitude of any vector is less then its x component will also be less because magnitude of component is dependent on the magnitude of vector

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Three point charges are on the x axis: −1 µC
Nina [5.8K]

Answer:

0.0078 N

Explanation:

The electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

The force is attractive if the two  charges have opposite sign, and repulsive if the two charges have same sign.

In this problem, we have:

q_1 = -1 \mu C = -1 \cdot 10^{-6}C located at x_1=-3 m

q_2=+9 \mu C = +9\cdot 10^{-6}C located at x_2=0 m

q_3 = -5 \mu C = -5\cdot 10^{-6} C located at x_3=+3 m

The force between charge 1 and charge 2 is:

F_{12}=k\frac{q_1 q_2}{(x_2-x_1)^2}=(8.99\cdot 10^9)\frac{(1\cdot 10^{-6})(+9\cdot 10^{-6})}{3^2}=0.0090 N

And since the two charges have opposite sign, the force is attractive, so the force on charge 1 is towards the right.

The force between charge 1 and charge 3 is:

F_{13}=k\frac{q_1 q_3}{(x_3-x_1)^2}=(8.99\cdot 10^9)\frac{(1\cdot 10^{-6})(5\cdot 10^{-6})}{6^2}=0.0012 N

And since the two charges have same sign, the force is repulsive, so the force on charge 1 is towards the left.

Therefore, the net  force on charge 1 is:

F=F_{12}-F_{13}=0.0090-0.0012 = 0.0078 N

towards the right.

5 0
3 years ago
A 250-kg crate is on a rough ramp, inclined at 30° above the horizontal. The coefficient of kinetic friction between the crate a
astraxan [27]

The force that is pushing the crate up the ramp is competing with at least another two forces, those being G force= defines the attraction to the earth and Ff, the friction between the crate and the rough material of the ramp

Any Force can be defined by the weigh of a particular body and the acceleration

the kinetic friction indicative would be defined by the report between the active force and the friction force, considering G

So 5000-22%×5000=250× a

a=3900/250 m/s

6 0
3 years ago
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Keith_Richards [23]

Answer:

independent variable

Explanation:

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Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only o
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5 0
3 years ago
1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es
bezimeni [28]

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

7 0
3 years ago
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