1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
drek231 [11]
3 years ago
14

190 kg of water is to be raised by a water pump to a height of 25 meters from the bottom of a well in 60 seconds. What should be

the minimum power rating of the pump in kilowatts and in horsepower?
Physics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

776.6 w

1.04 hp

Explanation:

given:

Mass, m = 190kg

height change, h = 25m

time elapsed, t = 60 s

acceleration due to gravity, g = 9.81 m/s²

Potential energy required raising 190 kg of water to a height of 25m

= mgh

= 190 x 9.81 x 25

= 46,597.5 J

Power required in 60 s

= Energy required ÷ time elapsed

= 46,597.5 ÷ 60

= 776.6 Watts  (Use conversion 1 W = 0.00134102 hp)

= 776.6 w x 0.00134102 hp/w

= 1.04 hp

You might be interested in
A spring scale hung from the ceiling stretches by 6.4 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl
dolphi86 [110]
In the first case, the force acting on the spring is the weight of the mass:
F=mg=(2.0 kg)(9.81 m/s^2)=19.6N
This force causes a stretching of x=6.4 cm=0.064 m on the spring, so we can use these data to find the spring constant:
k= \frac{F}{x}= \frac{19.6 N}{0.064 m}=306.3 N/m

In the second case, the first mass is replaced with a second mass, whose weight is
F=mg=(2.5 kg)(9.81 m/s^2)=24.5 N
And since we know the spring constant, we can calculate the new elongation of the spring:
x= \frac{F}{k}= \frac{24.5 N}{306.3 N/m}=0.080 m=8.0 cm
5 0
3 years ago
Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?
Licemer1 [7]

Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→  231P₉₀  ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

3 0
3 years ago
The magnetic field produced by a long straight current-carrying wire is
alexdok [17]

Answer:

proportional to the current in the wire and inversely proportional to the distance from the wire.

Explanation:

The magnetic field produced by a long, straight current-carrying wire is given by:

B=\frac{\mu_0 I}{2 \pi r}

where

\mu_0 is the vacuum permeability

I is the current intensity in the wire

r is the distance from the wire

From the formula, we notice that:

- The magnitude of the magnetic field is directly proportional to I, the current

- The magnitude of the magnetic field is inversely proportional to the distance from the wire, r

Therefore, correct option is

proportional to the current in the wire and inversely proportional to the distance from the wire.

8 0
3 years ago
What is a likely consequence of preventing prescribed burns to forest ecosystems?
liraira [26]

The forest ecosystem will regain back its natural ecology compared to burning of the forest and other illegal activities done to the forest. And also, some of the animals living in that forest will live and those that are endangered will not be threatened.

5 0
2 years ago
A uniform rod is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The moment of inertia of t
emmasim [6.3K]

Answer:

Angular acceleration = 6.37rad/sec²

Approximately, Angular acceleration =

6.4 rad/sec²

Explanation:

Length of the rod = 2.0m long

Inclination of the rod (horizontal) = 30°

Mass of the rod is not given so we would refer to it as = M

Rotational Inertia of the Rod(I) = 1/3ML²

Angular Acceleration = ?

There is an equation that shows us the relationship between Torque and Angular acceleration.

The equation is :

Torque(T) = Inertia × Angular Acceleration

Angular acceleration = Torque ÷ Inertia

Where:

Torque = L/2(MgCosθ)

Where M = Mass

L = Length = 2.0m

θ = Inclination of the rod (horizontal) = 30°

g = Acceleration due to gravity = 9.81m/s²

Inertia = 1/3ML²

Angular Acceleration =  (Mass × g × Cos (30°) × (L÷2)) ÷ 1/3ML²

Angular Acceleration =

(3 × g × cos 30°) ÷ 2× L

Angular Acceleration = (3 × 9.81m/s² × cos 30°) ÷ 2× L

Angular Acceleration = 3 × 9.81m/s² × cos 30°) ÷ 2× 2.0m

Angular Acceleration = 6.37rad/sec²

Approximately Angular Acceleration =

6.4rad/sec²

5 0
3 years ago
Other questions:
  • Suppose two vectors have unequal magnitudes. can their sum be zero? explain
    7·1 answer
  • The diagram shows a heat engine. In which area of the diagram is unusable thermal energy detected?
    13·2 answers
  • An blank <br> Used to determine the change of an object
    12·1 answer
  • Light waves from the sun can be converted to electricity through __________.
    7·1 answer
  • Why doesnt a ball roll on forever after being kicked at a soccer game
    13·1 answer
  • Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a hi
    15·1 answer
  • PLZ HELP, BRAINLIEST !!
    12·2 answers
  • A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have t
    15·1 answer
  • Can someone help please
    7·1 answer
  • What is the largest structure people have put into space?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!