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REY [17]
4 years ago
12

A vet weighs two puppies. The small puppy weighs 4 2/3 pounds. The large puppy weighs 4 2/3 times as much as the small puppy. Ho

w much does the large puppy weigh?
Mathematics
1 answer:
Maksim231197 [3]4 years ago
4 0
4 2/3 lbs = small puppy weight
4 2/3 times the small puppies weight = large puppy weight
          4 2/3 × 4 2/3  or 4 2/3^2  = 21.77777.... or in mixed number is 21 7/9 lbs
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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4 0
3 years ago
1. Which store had the highest demand both before and after the price increase?
Anna71 [15]

Answer:

The answer is Store 4

Step-by-step explanation:

As before the price increases, Store 4 has the highest price among other Stores. After price increases, Store 4 continued to has highest price among them

6 0
3 years ago
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In the xy-coordinate plane shown, line L passes through point C and has a slope of -2. A dilation of line L with center A and a
a_sh-v [17]

Answer:

Step-by-step explanation:

Dilation of a line about a point not on the line shifts the line but leaves the slope intact .

New line slope will be -2

As both A and C lie on a horizontal line y = 2, C' will also lie on the same line

The distance between A and C is 0 - 2 = -2

a scale factor of 3 means C' is -2(3) = -6 units left of A

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3 years ago
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