Question

1.Find the positive root of 3x² + 6 =9.​

Answer 1

Sqrt ( 3x^2 + 6 ) = 9

Do the square bothsides of the

Equation.

3x^2 + 6 = 81

3x^2 = 81 - 6

3x^2 = 75

Divide bothsides with 3

3x^2 / 3 = 75/ 3

x^2 = 25

Now ,

x = sqrt ( 25 )

x = + or - 5

But we need pisitive root ,

therefore ,

x = 5