I need help!! PLEASE PLEASEE HELP ME

option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

1 year ago

The graph below shows the distances, in miles, that a dragonfly can travel in a certain number of hour. Based on the graph, what

Evgen [1.6K]

The graph provides distance as a linear function of time.
The y-intercept is zero.

The line passes through (0,0) and (6,120).
Calculate the slope.
m = (120 - 0)/(6 - 0) = 20

The equation of the line is
d = 20t
where
t = time, hours
d = distance, miles

Therefore distance is the dependent variable.
When t = 24 hours, the distance is 20*24 = 480 miles.

Answers:
(a) Distance is the dependent variable
(b)The equation relating the two variables is
d = 20t
where
t = time, hours
d = distance, miles
(c) In 24 hours, the dragonfly will travel 480 miles.

6 0

2 years ago

Sydney invested $440 in an account paying an interest rate of 5.6% compounded daily. Assuming no deposits or withdrawals are mad

stealth61 [152]

Answer:

The time required to get a total amount of $ 640.00 from compound interest on a principal of $ 440.00 at an interest rate of 5.6% per year and compounded 365 times per year is approximately 7 years.

Step-by-step explanation:

Given

Principle Amount P = $440

Accrued Amount A = $640

Interest rate r = 5.6% = 0.056

Compounded daily n = 365

To determine:

Time period t = ?

Using the formula

$A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}$

solving for t

t = ln(A/P) / n[ln(1 + r/n)]

substituting the values A = 640, P = 440, n = 365 and r = 0.056

t = ln(640/440) / ( 365 × [ln(1 + 0.00015342465753425/365)] )

t = 6.691

t ≈ 7 (nearest year)

Therefore, the time required to get a total amount of $ 640.00 from compound interest on a principal of $ 440.00 at an interest rate of 5.6% per year and compounded 365 times per year is approximately 7 years.

4 0

2 years ago

Six students are working on math. Two-thirds of them are working on fractions. How many students are working on fractions?

dybincka [34]

(2/3)- students working on math
6-total students
(2/3) of 6 students+= (2/3)x6 = (12/3) = 4

3 0

2 years ago

make the indicated conversion assume a 360-day year as needed,8months to simplified fraction of a year

balandron [24]

<span>8 months to simplified fraction of a year:

There are 12 months in a year.

8 month = 8/12 = 2/3</span>

6 0

2 years ago