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3 years ago

The sum of eight times a number and negative exceeds twelve.

Mathematics

1 answer:

11111nata11111 [884]3 years ago

6 0

Answer:8x + -4 > 12

8x > 16

x > 2

Step-by-step explanation:

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Answer:

$\dfrac{-x}{3}$ should be added to the given equation.

Step-by-step explanation:

Let a is added to the given equation.

According to the given condition,

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Step-by-step explanation:

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2 years ago

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Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.

stepladder [879]

Answer:

$e(2x^{2} -12x)-4x^{2}+C$

Step-by-step explanation:

We have been given an indefinite integral as $\int \left(4x-12\right)e-8x\:dx$ . We are asked to find the given integral.

Let us solve our given problem.

$\int \left(4x-12\right)e\:dx-\int 8x\:dx$

Take out constant:

$e\int \left(4x-12\right)\:dx-8\int x\:dx$

$e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx$

$e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C$

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$e(2x^{2} -12x)-4x^{2}+C$

Therefore, our required integral would be $e(2x^{2} -12x)-4x^{2}+C$ .

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3 years ago

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charle [14.2K]

Answer:

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3 years ago

The sum of eight times a number and negative exceeds twelve.​

The sum of eight times a number and negative exceeds twelve.