Since it is looking for the sum
at S3, replace n with 3 , 2, and 1 , solve the equation and add all of answers together
when s = 3 the equation becomes 5(1/3)^3-1
5(1/3)^2 = 5/9
when s = 2 the equation becomes 5(1/3)^2-1
5(1/3)^1 = 5/3
when s = 1 the equation becomes 5(1/3)^1-1
5(1/3)^0 = 5
5/9 + 5/3 + 5 = 65/9
the answer is the 3rd choice
<span>dividend x3 - 11x2 + 16x + 84
- divisor * x2 x3 - 7x2
remainder - 4x2 + 16x + 84
- divisor * -4x1 - 4x2 + 28x
remainder - 12x + 84
- divisor * -12x0 - 12x + 84
remainder 0
Quotient : x2-4x-12 Remainder: 0
Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .
-12 + 1 = -11
-6 + 2 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2
x2 - 6x + 2x - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-6)
Add up the last 2 terms, pulling out common factors :
2 • (x-6)
Step-5 : Add up the four terms of step 4 :
(x+2) • (x-6)
Which is the desired factorization
Final result :
(x + 2) • (x - 6) • (x - 7)</span>
He finished the job at 1:15 P.M.
Answer:
40%
Step-by-step explanation:
The first step is to calculate the unit selling price
= total sales/number of units
= 200,000/50,000
= $4
The unit variable expense can be calculated as follows.
= total variable expense/number of units
= 120,000/50,000
= $2.4
The contribution margin per unit can be calculated as follows
=selling price per unit- variable cost.
= $4-$2.4
= $1.6
Therefore the contribution margin ratio can be calculated as follows.
= $1.6/$4
= 0.4×100
= 40%
Answer:
Ada should buy 385 eggs from the store.
Step-by-step explanation:
Given that you know that Ada can make 40 egg tarts using 110 eggs, you can use a rule of three to find the amount eggs to make 140 egg tarts:
40 egg tarts → 110 eggs
140 egg tarts → x
x=(140*110)/40=385 eggs
According to this, the answer is that Ada should buy 385 eggs from the store.
