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Ierofanga [76]
4 years ago
7

PLEASE HELP WILL GIVE ANSWER BRAINLIEST

Mathematics
2 answers:
SpyIntel [72]4 years ago
7 0
First simplify the exponents.

(14)^2 = 196

(2)^3 = 8

(-6)^2 = 36

(-1)^3 = -1

(4)^2 = 16

Now, multiply them.

(196)(8) / (36)(-1)(16)

1568 / -576

Simplify and reduce the fraction with the GCF of 32.

49 / -18

Your answer is B. -49/18

Rudiy274 years ago
5 0
Hi there! It's b hope this helps!
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Identify the domain and range of the function:
Allisa [31]
I think the domain is (0,2,4,8) and the range is (4,6 and 8) also your learning this in high school?
8 0
3 years ago
prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact
Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable  on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that  limit property of an  integral

\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt

\int_{a}^{b} fdt=f(b)-f(a)....(Equation I)

Using above property of integral then we get

\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt......(Equation II)

Substitute equation I and equation II are equal

Then we get

\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}

\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)

\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)

Therefore, \int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt.

Hence, the value of function does not change after changing the value of function at c.

6 0
3 years ago
Convert 900 cm/hour into cm per min
balu736 [363]

Answer: 15 cm/min

Step-by-step explanation:

900÷60

60=hour

8 0
4 years ago
Read 2 more answers
F(1)=-12, f(n)=2f(n-1) <br> find first 4 terms
amid [387]
<h3>First four terms are:   -12, -24, -48, -96</h3>

============================================

Explanation:

The notation f(1) = -12 tells us that the first term is -12.

The equation f(n) = 2*f(n-1) indicates that we're multiplying the (n-1)th term by 2 to get the nth term. Basically we multiply each term by 2 to get the next term.

-12*2 = -24

-24*2 = -48

-48*2 = -96

So the first four terms are -12, -24, -48, -96.

-----------------------------------

Alternative Approach

f(1) = -12 .... first term

f(n) = 2*f(n-1) ... nth term recursive formula

f(2) = 2*f(2-1) ... plug in n = 2

f(2) = 2*f(1)

f(2) = 2*(-12) ... plug in f(1) = -12

f(2) = -24 ... second term

f(n) = 2*f(n-1) .... resetting for the next computation

f(3) = 2*f(3-1) ... plug in n = 3

f(3) = 2*f(2)

f(3) = 2*(-24)  ... plug in f(2) = -24

f(3) = -48 .... third term

f(n) = 2*f(n-1) ... one more reset

f(4) = 2*f(4-1) .... plug in n = 4

f(4) = 2*f(3)

f(4) = 2*(-48) ... plug in f(3) = -48

f(4) = -96 ... fourth term

We get the first four terms to be -12, -24, -48, -96, which was the same as earlier.

4 0
3 years ago
There are 80 guards and 32 forwards in Ben's basketball league.
xxTIMURxx [149]

Answer:


Step-by-step explanation:

The greatest common factor between 32 and 80 is 16 not 8.  

32 (forwards) / 16 (teams) = 2 forwards on each team.

80 (guards) / 16 (teams) = 5 guards on each team.

6 0
3 years ago
Read 2 more answers
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