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AnnZ [28]
4 years ago
5

5 times 5 is that 25 because I have a text

Mathematics
1 answer:
loris [4]4 years ago
5 0

Answer:

5×5 is equal to 25

.......

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When writing a equation how do you know where to put the equal sign ?
elena55 [62]

Answer:

The equal sign is generally placed at the separation between the left hand side and the right hand side

Step-by-step explanation:

Basically a typical equation has two parts, and one part is seen to be equal to the other part, and they are:

<h3>1. The left hand side</h3><h3>2. The right hand side</h3>

Generally equations are expressed algebraically,that is using letters/ alphabets and symbols to express mathematical relations

The left hand side mostly is the solution of the equation, while the right hand side contains symbols, alphabets used to find solution to the equation.

 

5 0
3 years ago
Which two binomials in part A didn't have an equivalent factored form? What made these expressions different from the
dalvyx [7]

Answer:

The binomials 16x2 + 9 and x2 + 16 didn’t have an equivalent factored form. Both are sums of perfect squares instead of differences.

Step-by-step explanation:

Official answer

4 0
4 years ago
Find the y-intercept of the line on the graph.
balandron [24]
The y intercept is - 1

It is where the line touches or crosses the y axis
3 0
3 years ago
Sunhee had four plastic shapes a square, a circle, and a pentagon in how many ways can she line up the four shapes of the circle
julsineya [31]

Answer:

only three shapes are mentioned.

But anyhow, 4 shapes allow the following reasoning...

you can start lining up with any of the for shapes, so you have 4 possibilities, for the second position you have 3 possibilities, for the third 2 and for the last only 1.

so 4*3*2*1= 24 possible ways

but with the added rule to keep the circle and the square apart, we have to reduce the number.

by the same step-by-step reasoning we get

4 possibilities for the 1st item

only 2 possibilities for the 2nd item

(if 1st is square or circle, the other one's not an option, if it's not we have to choose one of them to not place them both at point 3 and 4)

only 1 choice for the 3rd item

(reasoning as above, if 2nd is square or circle, we have to the only other, if it isn't, we can put it here at 3rd position)

plus scenarios where either square or circle are on 1st point, the other's on 4th.

I guess that makes 14 possible arrangements

5 0
3 years ago
Please help! 20 POINTS
dimulka [17.4K]
C= 7 and 1 hope this helps!
5 0
4 years ago
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