All categories

2 years ago

Help needed asap deadline is approaching

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

8 0

Your answer will be f(x) = 5 because, if we look at the table, no matter what x value we plug into the function, we will always get 5.

You might be interested in

PLEASE HELP

ruslelena [56]

Answer:

Rosaria purchased 50 bracelets and 70 necklaces

Step-by-step explanation:

Let the number of bracelets be b and the number of necklaces be n

b + n = 120 •••••(i)

Secondly;

10b + 11n = 1270 ••••(ii)

Total cost of b bracelets at 10 per 1 is 10b

Total cost of n bracelets at 11 per 1 is 11n

Adding both gives 1270

From i, b = 120-n

Substitute this into ii

10(120-n) + 11n = 1270

1200 - 10n + 11n = 1270

n = 1270-1200

n = 70

b = 120-n

b = 120-70

b = 50

4 0

2 years ago

Can someone please answer this question

aniked [119]

Option "D" would be your answer.

- KJ, JL, LK

7 0

2 years ago

Read 2 more answers

0.75 is the square root of what value?

lina2011 [118]

0.75^2 = 0.5625.....sq rt 0.5625 = 0.75

4 0

2 years ago

Read 2 more answers

Solve the following matrix equations: (matrices)

Masja [62]

Step-by-step explanation:

$3X + \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} = \begin{pmatrix} - 1 & 6 \\ 10 & 14 \end{pmatrix} \\ \\ 3X = \begin{pmatrix} - 1 & 6 \\ 10 & 14 \end{pmatrix} - \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} \\ \\ 3X = \begin{pmatrix} - 1 - 2 & 6 - 3 \\ 10 - 4 & 14 - 5 \end{pmatrix}\\ \\ 3X = \begin{pmatrix} - 3 & 3 \\ 6 & 9\end{pmatrix}\\ \\ X = \frac{1}{3} \begin{pmatrix} - 3 & 3 \\ 6 & 9\end{pmatrix}\\ \\ X = \begin{pmatrix} \frac{ - 3}{3} & \frac{3}{3} \\ \\ \frac{6}{3} & \frac{9}{3} \end{pmatrix}\\ \\ \huge \red{ X} = \purple{ \begin{pmatrix} - 1 &1 \\ 2 & 3 \end{pmatrix}}$

$3X + 2I_3=\begin{pmatrix} 5 & 0 & -3 \\6 & 5 & 0\\ 9 & 6 & 5\end{pmatrix} \\\\3X + 2\begin{pmatrix} 1 & 0 & 0\\ 0 & 1 & 0\\ 0 & 0 & 1\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\6 & 5 & 0\\ 9 & 6 & 5 \end{pmatrix} \\\\3X + \begin{pmatrix} 2 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 2\end{pmatrix} =\begin{pmatrix} 5 & 0 & - 3\\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} \\\\3X =\begin{pmatrix} 5 & 0 & -3 \\ 6 & 5 & 0 \\ 9 & 6 & 5 \end{pmatrix} - \begin{pmatrix} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{pmatrix} \\\\3X =\begin{pmatrix} 5-2 & 0-0 & -3-0 \\ 6-0 & 5-2 & 0-0 \\ 9-0 & 6-0 & 5-2 \end{pmatrix} \\\\3X =\begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X =\frac{1}{3} \begin{pmatrix} 3 & 0 & - 3 \\ 6 & 3 & 0 \\ 9 & 6 & 3 \end{pmatrix} \\\\X =\begin{pmatrix} \frac{3}{3} & \frac{0}{3} & \frac{-3}{3} \\\\ \frac{6}{3} & \frac{3}{3} & \frac{0}{3} \\\\ \frac{9}{3} & \frac{6}{3} & \frac{3}{3} \end{pmatrix} \\\\\huge\purple {X} =\orange{\begin{pmatrix} 1 & 0 & - 1\\ 2 & 1 & 0 \\ 3 & 2 & 1 \end{pmatrix}}\\$

8 0

3 years ago

A building with a height of 14 m casts a shadow that is 16 m long while a taller building casts a 24 m long shadow. What is the

uranmaximum [27]

26 i am not really sure cuz what i did was 16-14= 2
2+24= 26

5 0

2 years ago

Read 2 more answers