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VladimirAG [237]
3 years ago
5

S=n(a1+an)/2 gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Mathematics
2 answers:
juin [17]3 years ago
6 0

Just took the quiz.

The answer is an=2S-a1n/n

Norma-Jean [14]3 years ago
4 0
The given formula is
S= \frac{n}{2} (a_{1}+a_{n})

Multiply each side by 2.
2S=n(a_{1}+a_{n})

Divide each side by n.
\frac{2S}{n} =a_{1} + a_{n}

Subtract a₁ from each side.
\frac{2S}{n} - a_{1} = a_{n}

Answer: a_{n} =  \frac{2S}{n} - a_{1}
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A study was performed to investigate whether teens and adults had different habits when it comes to consuming meat-free meals. I
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Answer:

H₀ should be rejected at CI 95% .

Then the proportion of adults with 95 % CI is bigger than the proportion of teen

Step-by-step explanation:

From adult sample:

n₂ = 2323

x₂ = 1601

p₂ = 1601 / 2323         p₂  = 0,689       or    p₂ = 68,9%

From teen sample:

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To either prove or reject the above statement we have to develop a difference of proportion test according to:

Hypothesis test:

Null Hypothesis                   H₀             p₁  =  p₂

Alternative Hypothesis       Hₐ             p₂  > p₁

So is a one-tail test to the right

We can establish a confidence interval of 95 % then  α = 5 %

or    α = 0,05

As the samples are big enough we will develop a z test

Then  z(c)  for α = 0,05   from z table is     z(c) = 1,64

To calculate z(s)

z(s) = ( p₂  -  p₁ ) / √p*q* ( 1/n₁  + 1/n₂ )

where p = ( x₁ + x₂ ) / n₁ + n₂       p = 555 + 1601 / 875 + 2323

p = 2156/3198       p = 0,674

and   q = 1 - 0,674        q = 0,326

z(s) = ( 0,689 - 0,634 ) / √0,674*0,326 ( 1/875 + 1 / 2323

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z(s) = 0,055 / 1,85*10⁻²

z(s) = 5,5/1,85

z(s) = 2,97

Comparing  z(s) and z(c)     z(s) > z(c)

Then z(s) is in the rejection region we reject H₀.

We can claim that the proportion of adult eating at least one meat-free meal is bigger than the proportion of teen

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