Answer:
Step-by-step explanation:

Answer:
425
Step-by-step explanation:
Let
x-------> the first number
y------> the second number
we know that


equation 

equation 
substitute equation 1 in equation 2

using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is

Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have

and from the right-angled triangle WAB, we have'

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
Answer:
8 baseballs : 4 gloves
4 baseballs : 2 gloves
16 baseballs : 8 gloves
2 baseballs : 1 glove
10 baseballs : 5 gloves
Step-by-step explanation:
I think It's just asking to put some ratios that go with the one given.