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Scrat [10]
3 years ago
6

For an annual membership fee of $500, Mr.Bailey can join a country club that would allow him to play a round of golf for $35. Wi

thout the membership, the country club charges $55 for each round of golf. How many rounds can he play for the cost to be the same with and without a membership?
Mathematics
1 answer:
mote1985 [20]3 years ago
6 0
He would have to play 11 games.  and 3 games plus a membership in order to equal the same amount of 605
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2/3 lies between 1 and 2

Option C

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I need help with this ​
LuckyWell [14K]

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1st - Yes ; 2nd - Yes ; 3rd - Yes ; 4th - No

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which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21 ? Select each correct answer. (−1, −6) (−3, 3) (11
Valentin [98]

Answer:

see explanation

Step-by-step explanation:

To determine which ordered pairs are solutions to the equation

Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.

(- 1, - 6)

3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution

(- 3, 3)

3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution

(11, 3)

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(7, 0)

3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution

The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation

3 0
3 years ago
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the value of a collectible coin can be represented by the equation y=2x+9.74 where x represents the number of years that consuel
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Step-by-step explanation:

I got it right (:

4 0
3 years ago
What is the simplified form of x+2/x^2-3x-10 * x-3/x^2+x-12
Vinvika [58]
I mean based on your possible answers, the third one is correct,but you can go further that that, in the steps i will note when you've came to the "answer"

\frac{x + 2}{  {x}^{2}  - 3x - 10  }  \times  \frac{x - 3}{ {x}^{2} + x - 12 }
\frac{x + 2}{ {x}^{2} + 2x - 5x - 10 }  \times  \frac{x - 3}{ {x}^{2} + 4x - 3x - 12 }
\frac{x + 2}{x(x + 2) - 5(x + 2)}  \times  \frac{x - 3}{x(x + 4) - 3(x + 4)}
\frac{x + 2}{(x + 2) \times (x - 5)}  \times  \frac{x - 3}{(x + 4) \times (x  - 3)}
\frac{1}{(x + 4) \times (x + 5)}
and basically that's the "answer", but you can simplify more.

\frac{1}{ {x}^{2}  + 4x - 5x - 20}
\frac{1}{ {x}^{2} - x - 20 }
Hope that's helpful
3 0
3 years ago
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