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SCORPION-xisa [38]
3 years ago
15

Find fractional notation for the infinite sum (these are geometric series) 0.1919191919

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0
Let x = 0.191919...
Now, we want to find some sort of relationship with x and 0.191919...

If we multiply x by 100, we get:
100x = 19.19191919...

Now, it's clear that the decimal places will cancel when we subtract it:
100x - x = 19.19191919... - 0.19191919...
99x = 19

Solving for x, we get:
x = \frac{19}{99}
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Answer:

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Step-by-step explanation:

6 0
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Otis paints the interior of a home for $45 per hour plus $75 for supplies. Shireen paints the interior of a home for $55 per hou
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Step-by-step explanation:

you should only make one equation:

75 + 45x = 30 + 55x

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45 = 10x

Divide by 10 and get:

4.5 = x

After 4.5 hours, the cost is equal for either worker.

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3 years ago
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4 (b - 3 ) = 6 steps in order from first to last
Amiraneli [1.4K]

Answer:

B= 9/2 Hope this helped <3

Step-by-step explanation:

Let's solve your equation step-by-step.

4(b−3)=6

Step 1: Simplify both sides of the equation.

4(b−3)=6

(4)(b)+(4)(−3)=6(Distribute)

4b+−12=6

4b−12=6

Step 2: Add 12 to both sides.

4b−12+12=6+12

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4 years ago
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A company developed the following linear model to help budget annual expenses over time. In this model, x represents the number
olasank [31]
2010: 227681
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and so on
8 0
4 years ago
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
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