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MA_775_DIABLO [31]
3 years ago
15

Please help again thank you in advance

Mathematics
2 answers:
mojhsa [17]3 years ago
7 0

Answer:

20 units

Step-by-step explanation:

Since the triangle is equilateral then all 3 sides are equal in length.

Equate any 2 sides and solve for x

4x = 3x + 5 ( subtract 3x from both sides )

x = 5

hence

4x = 4 × 5 = 20

3x + 5 = (3 × 5) + 5 = 15 + 5 = 20

7x - 15 = (7 × 5) - 15 = 35 - 15 = 20

The lengths of the sides are 20 units

Crazy boy [7]3 years ago
7 0

Answer:

20-20-20(20 on each side)

Step-by-step explanation:

Okay, so what it's asking is to find 'x' and plug it in to find the missing sides. But, they all are equal to one another.

So the equation could be something like this:

4x=3x+5(Just to find x)

-3x  -3x

Then you'd have x=5

You'd plug it in and you'd have your answer of 20 for each side

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What is the radian measure of the central angle of a circle of radius 1.5 meter that intercepts an arc of length 600 centimeters
Maksim231197 [3]

Radian measure of the central angle is 4 radian

<em><u>Solution:</u></em>

Given that,

A circle of radius 1.5 meter that intercepts an arc of length 600 centimeters

To find: Radian measure of the central angle

Let us find the circumference of circle

The circumference of circle is given as:

\text{ circumference of circle } = 2 \pi r

Where "r" is the radius of circle

\text{ circumference of circle } = 2 \times \pi \times 1.5 = 3 \pi

Therefore circumference of circle = 3 \pi meters , which subtends central angle of  2 \pi radian

Given that arc of length 600 centimeters. Let us convert 600 centimeter to meter

We know that, to convert centimeter to meter divide the length value by 100

\text{ 600 centimeter } = \frac{600}{100} \text{ meter } = 6 \text{ meter}

<u><em>Therefore arc of 6 meter will subtend a central angle of:</em></u>

\rightarrow \frac{6}{3 \pi} \times 2 \pi = 4

Therefore radian measure of the central angle is 4 radian

7 0
3 years ago
The upper arm length of females over 20 years old in a country is approximately Normal with mean 35.8 centimeters (cm) and stand
lana [24]

Answer:

a) The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

b) 16% of women over 20 have upper arm lengths less than 33.3 cm.

Step-by-step explanation:

The Empirical Rule(68-95-99.7 Rule) states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 35.8 cm

Standard deviation = 2.5 cm

(a) What range of lengths covers almost all (99.7%) of this distribution?

This range is from 3 standard deviations below the mean to three standard deviations above the mean.

So from 35.8 - 3*2.5 = 28.3 cm to 35.8 + 3*2.5 = 43.3 cm

The range of lengths from 28.3 cm to 43.3 cm covers almost all (99.7%) of this distribution.

(b) What percent of women over 20 have upper arm lengths less than 33.3 cm?

68% of the women over 20 have upper arm length between 33.3 cm and 38.3 cm. The other 32% have upper arm length lower than 33.3 cm or higher than 38.3. The distribution is symmetric, so 16% of the have upper arm length lower than 33.3 cm and 16% have upper arm length higher than 38.3 cm

So 16% of women over 20 have upper arm lengths less than 33.3 cm.

4 0
3 years ago
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