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2 years ago

Can someone help me with this problem?

Mathematics

1 answer:

Tatiana [17]2 years ago

8 0

Answer:

Step-by-step explanation:

if not c it's B

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Jeanne thinks that x+x is the same as x•x. Is this true? Why? Why not?

NARA [144]

Generally, x • x is accepted to mean "x times x" or "x multiplied by x"

and x+x means "x plus x" or "x added to x"

let's try by subsituting numbers for them
if we can find one case where the statement "x+x is the same as x•x" is false, then it is not true

let's try x=4
x+x=x•x
4+4=4•4
8=16
false

so it is not true
(x+x is equal to 2x, so therefor if we were to solve 2x=x•x, we would get that it is only true for x=2 and x=0)

it is not always true

6 0

2 years ago

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Solve the equation A+b - c =180 for C

spayn [35]

A = 180
b = 180
c = 180

180+180-180 = 180

5 0

3 years ago

Sam the owl is looking down at a 24° angle from the top of a tree that is 10 ft tall, when he spots a bird on the ground. How fa

Liula [17]

Answer:

24.59 feet

Step-by-step explanation:

Let x represent the distance between Sam and the bird.

We have been given that am the owl is looking down at a 24° angle from the top of a tree that is 10 ft tall, when he spots a bird on the ground. We are asked to find the distance between Sam and the bird.

We can see from our attachment that Sam, the bird and angle of depression forms a right triangle with respect to ground. We can see that side 10 ft is opposite side and and side x is hypotenuse for the 24 degree angle.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(24^{\circ})=\frac{10}{x}$

$x=\frac{10}{\text{sin}(24^{\circ})}$

$x=\frac{10}{0.406736643076}$

$x=24.5859333557$

$x\approx 24.59$

Therefore, the bird is approximately 24.59 feet away from Sam.

8 0

2 years ago

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

2 years ago

Algebra Please help Simplify (2√5+3√7)^2

GREYUIT [131]

4√5+9√7

Hope this helps!

4 0

2 years ago

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