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Nata [24]
3 years ago
15

Find the perimeter of parallelogram ABCD with vertices A(–5, 6), B(2, 6), C(1, –2), and D(8, –2).

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0
Since in A and B we have the same y value, 2-(-5)=7 and that's one side. For A to C (we connect A to C since they are both the ones on the left), we use the distance formula to get sqrt((-5-1)^2+(6-(-2))^2=sqrt(36+64)=sqrt(100)=10. Since there are 2 equal pairs of sides in a parallelogram, we get 7*2+10*2=34
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Why is it important to know the different properties of three-dimensional figures
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4 0
3 years ago
Answer ASAP please, Will give brainliest.
nikdorinn [45]

Answer:

see below

Step-by-step explanation:

The measure of a minor arc is the same as the angle that forms it.

1. Since ∠GBJ = 90°, the answer is 90°.

2. ∠HBI = 180° - 151° = 29° so the answer is 29°.

3. ∠HBJ = 180° so the answer is 180°.

4. The reflex angle ∠GBI = 90 + 151 = 241° so the answer is 241°/

5. Since ∠GBJ = 90°, the reflex angle ∠GBJ = 360 - 90 = 270° so the answer is 270°.

6. ∠GBH = 180 - 90 = 90° so the reflex angle ∠GBH = 360 - 90 = 270° so the answer is 270°.

4 0
3 years ago
What is 1/6d+2/3 = 1/4(d-2)
GenaCL600 [577]
1/6d + 2/3 = 1/4(d - 2)

First, simplify \frac{1}{6} d to \frac{d}{6} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{1}{4} (d - 2)
Second, simplify \frac{1}{4} (d - 2) to \frac{d-2}{4} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{d-2}{4}
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
Sixth, simplify 3d - 6 - 2d to d - 6 / Your problem should look like: 8 = d - 6
Seventh,add 6 to both sides. / Your problem should look like: 8 + 6 = d
Eighth, simplify 8 + 6 to 14 / Your problem should look like:14 = d
Ninth, switch sides. / Your problem should look like: d = 14

Answer: d = 14

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