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2 years ago

8

Hayley is considering two gym membership plans. The plans are detailed here.

1 answer:

Lera25 [3.4K]2 years ago

5 0

Answer:

aye she probally not gonna go every day she polly gonna got twice so just pay 4 every visit

Step-by-step explanation:

You might be interested in

If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG

velikii [3]

we have that

*-------------------------*--------------------------------*

E F G

EF=2x-12

FG= 3x-15

EG=23

we know that

EF + FG = EG

so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15

therefore

the answer part a) is

the value of x is 10

the answer part b) is

the value of EF is 8

the answer part c) is

the value of FG is 15

6 0

2 years ago

How does someone find the measurement of a triangle's side by the given angles inside the triangle?

romanna [79]

You use the formula given and it usually involves dividing

8 0

2 years ago

PlZZZ HELP<br><br> Which of the following is equal to

stealth61 [152]

Answer:

1st option

Step-by-step explanation:

4 $\frac{1}{3}$ ÷ 2 $\frac{3}{5}$ ( change mixed numbers into improper fractions )

= $\frac{13}{3}$ ÷ $\frac{13}{5}$

To perform the division

leave 1st fraction, change ÷ to × , turn 2nd fraction ' upside down'

= $\frac{13}{3}$ × $\frac{5}{13}$

7 0

1 year ago

Read 2 more answers

Given: AB = BC Prove: B is the midpoint of AC. A line contains point A, B, C. A flow chart has 3 boxes that go from top to botto

aliina [53]

Answer:

flowchart proof

Step-by-step explanation:

3 0

2 years ago

The value 5 is an upper bound for the zeros of the function shown below.

Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

Step-by-step explanation:

Given

$f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$

We know the rational zeros theorem such as:

if $x=c$ is a zero of the function $f(x)$ ,

then $f(c) = 0$ .

As the $f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$ is a polynomial of degree $4$ , hence it can not have more than $4$ real zeros.

Let us put certain values in the function,

$f(5) = 448$ , $f(4) = 126$ , $f(3) = 0$ , $f(2) = -20$ ,

$f(1) = 0$ , $f(0) = 18$ , $f(-1) = 16$ , $f(-2) = 0$ , $f(-3) = 0$

From the above calculation results, we determined that $4$ zeros as

$x = -3, -2, 1,$ and $3$ .

Hence, we can check that

$f(x) = (x+3)(x+2)(x-1)(x-3)$

Observe that,

$for x > 3$ , $f(x)$ increases rapidly, so there will be no zeros for $x>3$ .

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

5 0

2 years ago