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4 years ago

Find the area and perimeter of compound shape. Please help

Mathematics

1 answer:

Mekhanik [1.2K]4 years ago

5 0

Answer:

A=140m² and P=54m

Step-by-step explanation:

In order to find the perimeter or area, we are going to first need to find the lenghts of the missing sides. There are two of them, we are going to refer to one as the shorter one and the other as the longer one.

Shorter One = 12-8

Shorter One = 4

Longer One = 15-5

Longer One = 10

From this we can then add the side lengths to find the perimeter of the figure.

Perimeter=5+15+12+8+4+10

Perimeter=20+20+14

Perimeter=54

The perimeter of the figure is 54m, therefore we can eliminate two of the answer choices.

Next, we need to find the area of the figure. The easiest way is to cut the figure into two pieces, I chose to do it by cutting a long rectangle, and then add their areas together.

A=(5*12)+(10*8)

A=60+80

A=140

Therefore the correct answer choice is A=140m² and P=54m

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ASHA 777 [7]

Answer:

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Step-by-step explanation:

So, since all the sides are equal, you can just take two of the sides and set em equal to each other to find x and then, solve for AB

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Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

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Read 2 more answers

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horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

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For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

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Answer:

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Step-by-step explanation:

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