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Virty [35]
3 years ago
12

Find the area and perimeter of compound shape. Please help

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

A=140m² and P=54m

Step-by-step explanation:

In order to find the perimeter or area, we are going to first need to find the lenghts of the missing sides. There are two of them, we are going to refer to one as the shorter one and the other as the longer one.

Shorter One = 12-8

Shorter One = 4

Longer One = 15-5

Longer One = 10

From this we can then add the side lengths to find the perimeter of the figure.

Perimeter=5+15+12+8+4+10

Perimeter=20+20+14

Perimeter=54

The perimeter of the figure is 54m, therefore we can eliminate two of the answer choices.

Next, we need to find the area of the figure. The easiest way is to cut the figure into two pieces, I chose to do it by cutting a long rectangle, and then add their areas together.

A=(5*12)+(10*8)

A=60+80

A=140

Therefore the correct answer choice is A=140m² and P=54m

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Answer: Opens up, has a minimum

Step-by-step explanation:

If the x^2 term is positive the parabola opens up, if it is negative it opens down. Minimum always goes with up, maximum with down

7 0
3 years ago
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Jobisdone [24]

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6 0
2 years ago
The expression 21 - (2x + 3)2 + 4 (1 - 1) + z3 can be simplified into the form
mr Goodwill [35]

Answer:

A=z

B=-2

C=0

D=30

Step-by-step explanation:

First lets simply the equation

21 - (2x +3)2 + 4(1-1) + z^3

21 - (2x^2 + 9) + 4(0) + z ^3

21 - 2x^2 + 9 + z^3

- 2x^2 + z ^3 + 30

This means that:

A=z

B=-2

C=0

D=30

5 0
3 years ago
Can you guys help me solve this problem
Maslowich

PLEASE. MARK ME AS BRAINLIEST ANSWER.

8 0
2 years ago
Put these numbers in order from greatest to least.<br> 1 6/8,-10/25,-18/25,1
goldenfox [79]

\textsf{Hey there!}

\textsf{Put these numbers in order from GREATEST to LEAST}

\bullet{\mathsf{ \ 1\dfrac{6}{8}}}

\bullet\mathsf{\ -\dfrac{10}{25}}

\bullet{\mathsf{\ -\dfrac{18}{25}}}

\bullet{\textsf{ 1}}

\star\textsf{ We know that fractions, decimals, negatives are BELOW 0 (on the left} \textsf{of 0)}

\star\textsf{ \& we also know that positives and real numbers is/are ABOVE 0 (to the right} \textsf{of 0)}

\textsf{Now we can answer your question}

\blacksquare \ \mathsf{1\dfrac{6}{8} = \dfrac{14}{8} = 1.75}

\blacksquare\ \mathsf{-\dfrac{10}{25} = -0.40}

\blacksquare\ \mathsf{- \dfrac{18}{25} = -0.72}

\blacksquare \ \mathsf{1 = 1}

\textsf{Look carefully at the stuff converted to the decimal or regular number \& } \textsf{you will  have your answer from \underline{greatest} to \underline{least}}

\boxed{\textsf{If you solved correctly you  SHOULD have: \boxed{\mathsf{\dfrac{14}{8}, \ 1, \ - \dfrac{10}{25}\ ,\  -\dfrac{18}{25}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

5 0
3 years ago
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