Is either I’m blind and can’t see or the letter are way too small
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Step-by-step explanation:
We khow the sum and the product of the zeroes of this quadratic polynomial
Here is a trick :
when we khow the sum S and the product P ofvtwo numbers we can find them by solving :
x²-Sx+p=0
here S= -8 and P=12
so:
x²+8x+12=0
Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12
Δ= 8²-4*12 =16
the zeros are:
(-8-4)/2= -6
(-8+4)/2 = -2
verify:
-6+(-2)= -8
-2*(-6)= 12
now the polynomial quadratic is:
(x+6)(x+2)
Answer:
Step-by-step explanation:
N(17+x)=34x−r
17n+xn=34x-r
xn= 34x - r - 17n
xn-34x= -r - 17n
x(n-34)= -r - 17n
x= (-r - 17n)/(n-34)
Answer:
p = -2
Step-by-step explanation:
15 = -4p + 7
4p + 15 = 7
4p + 15 - 15 = 7 - 15
4p = -8
4p/4 = -8/4
p = -2