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lorasvet [3.4K]

3 years ago

8

What is the x intercept of f(x)=-6x+3

2 answers:

Assoli18 [71]3 years ago

6 0

The x intercept of <span>f(x)=-6x+3 is (.5, 0).</span>

katrin [286]3 years ago

3 0

<span>x intercept when y = 0
so
</span><span>-6x+3 = 0
-6x = -3
x = 1/2

answer
</span><span>x intercept (1/2 , 0)</span>

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The equation of a circle is A is x^2

Gala2k [10]

Answer: ??

Step-by-step explanation:

This might help :/

Area of a circle = pie r^

Circumference = 2pie r

3 0

3 years ago

A table is 4 ft high. A model of the table is 6 in. high. What is the ratio of the height of the actual table to the height of t

Sliva [168]

Answer:

8:1

Step-by-step explanation:

the actual table's height in inches is 4*12 = 48 inches.

48/6 = 8

so the ratio is 8:1.

5 0

3 years ago

Read 2 more answers

For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.

vampirchik [111]

Answer:

The angle between the given vectors u and v is $\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Step-by-step explanation:

Given vectors are $\overrightarrow{u}=(3,4)$ and $\overrightarrow{v}=(1,3)$

Now compute the dot product of u and v:

$\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)$

$=(3)(1)+(4)(3)$

$=3+12$

$=15$

Now find the magnitude of u and v:

$|\overrightarrow{u}|=\sqrt{3^2+4^2}$

$=\sqrt{9+16}$

$=\sqrt{25}$

$=5$

$|\overrightarrow{u}|=5$

$|\overrightarrow{v}|=\sqrt{1^2+3^2}$

$=\sqrt{1+9}$

$=\sqrt{10}$

$|\overrightarrow{v}|=\sqrt{10}$

To find the angle between the given vectors

$\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta$

$\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Therefore the angle between the vectors u and v is

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

3 0

3 years ago

Solve for x.<br><br> −4/5x+3/10<8/10

Genrish500 [490]

Answer:

for (−4/5)x + 3/10 < 8/10: solution is x > -5/8

for −4/(5x) + 3/10 < 8/10: solution is x > -8/5

Step-by-step explanation:

I'm not exactly sure if you mean -4 divided by 5x or (-4/5)x, so I've done both! :)

$-\frac{4}{5}x+ \frac{3}{10} < \frac{8}{10}$

subtract 3/10 from both sides: $-\frac{4}{5}x < \frac{5}{10}$

Divide both sides by 4/5: $-x < \frac{5}{8}$

Divide both sides by -1 (reverse sign): $x > -\frac{5}{8}$

$-\frac{4}{5x}+ \frac{3}{10} < \frac{8}{10}$

subtract 3/10 from both sides: $-\frac{4}{5x} < \frac{5}{10}$

Multiply both sides by 5x: $-4 < \frac{5}{2}x$

Divide both sides by 5/2: $x>- \frac{8}{5}$

6 0

2 years ago

Read 2 more answers

Element X decays radioactively with a half life of 6 minutes. If there are 790 grams of Element X, how long, to the nearest tent

frosja888 [35]

Answer:

It takes 27 minutes for the element to decay to 35 grams

Step-by-step explanation:

Given:

Initial amount = 790 grams

Final amount = 35 grams

Half life = 6 minutes

To find:

Time taken for the element to reduce into 35 grams = ?

Solutions

Time taken = $half life \times \frac{ log(\frac{ initial amount}{final amount})}{log(2)}$

On substituting the values given, Time taken

= $6 \times \frac{log(\frac{790}{35})}{log(2)}$

= $6 \times \frac{log(22.57)}{log(2)}$

= $6 \times 4.496$

= 26.97

= 27 minutes

7 0

3 years ago