Here's some code that might help, assuming that you are using JavaScript.
e = "Hello"
if(e === "Hello"){
alert(":D")
}else{
console.log("Um.")
}
I think that the answer is curly brackets.
Answer:
int k;
double d;
char s[10];
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Explanation
First Step (declare K, d, s) so they can store a integer
int k;
double d;
char s[10];
Second Step (read in an integer, a real number and a small word)
cin >> k >> d >> s;
Third Step ( print them out )
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Answer:
A) Malicious Association,
Hope this helps.
Explanation:
A. 5
b. as an unsigned int: 9. Normally a year is 365.25 days which would require 32-bits for an IEEE float.
c. 25
Answer:
Check the explanation
Explanation:
We can utilize the above algorithm with a little in modification. If in each of the iteration, we discover a node with no inward edges, then we we’re expected succeed in creating a topological ordering.
If in a number of iteration, it becomes apparent that each of the node has a minimum of one inward edge, then there must be a presence of cycle in the graph.
So our algorithm in finding the cycle is this: continually follow an edge into the node we’re presently at (which is by choosing the first one on the adjacency list of inward edges to decrease the running time).
Since the entire node has an inward edge, we can do this continually or constantly until we revisit a node v for the first time.
The set of nodes that we will come across among these two successive visits is a cycle (which is traversed in the reverse direction).
