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jek_recluse [69]
3 years ago
15

Again, suppose that n and r denote integer values where r > 0 and n ≥ 0. What are two "simple" values, say lowEnough and tooH

igh, such that lowEnough ≤ ⌊n√r⌋⌊nr⌋ < tooHigh. Explain based on your answer to the previous question.
Suppose you would like to know ⌊47226−−−−−√5⌋⌊472265⌋. Explain how you could find ⌊47226−−−−−√5⌋⌊472265⌋ using a guess and verify method. Note: Explain your answer by relating this problem to the number guessing game described earlier. Think about what would be an appropriate question to use in place of "Is secret_number < guess_number?" and think about good choices for the starting values of lowEnough and tooHigh.
Computers and Technology
1 answer:
enyata [817]3 years ago
6 0

Answer:

Answer explained

Explanation:

From the previous question we know that while searching for n^(1/r) we don't have to look for guesses less than 0 and greater than n. Because for less than 0 it will be an imaginary number and for rth root of a non negative number can never be greater than itself. Hence lowEnough = 0 and tooHigh = n.

we need to find 5th root of 47226. The computation of root is costlier than computing power of a number. Therefore, we will look for a number whose 5th power is 47226. lowEnough = 0 and tooHigh = 47226 + 1. Question that should be asked on each step would be "Is 5th power of number < 47227?" we will stop when we find a number whose 5th power is 47226.

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Write out code for a nested if statement that allows a user to enter in a product name, store the product into a variable called
OlgaM077 [116]

Answer:

product_name = input("Enter product name : ")

if product_name=="pen"or"book"or"box"or"pencil"or"eraser":

   if product_name == "pen":  

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       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "book":

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       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "box":  

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       print(f"Product Name: {product_name}\nCost: {amount} rupees")

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   if product_name == "eraser":

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Explanation:

The python program is a code of nested if-statements that compares the input string to five items of the first if-statement. For every item found, its code block is executed.

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Answer:

see explaination

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To create version to be able to purchase invention from the structure.

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c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi
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Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

  • Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
  • Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
  • Then, we get input from the user in variable "s" for the length of the loop.
  • Then, we set for the loop inside it, we get input in the variable "strng" from the user.
  • Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
  • Finally, we set for a loop to print the result.
4 0
3 years ago
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